Why getting indentation error while using if statement on python(android)

Answer 1

show us the code, or we can't help you ... 😬

Answer 2

You need to insert some space after an if-clause.

So not:

if 2>1:
print('yep')

But:

if 2>1:
print('yep')

Answer 3

x=int(input('First number'))
if x>4:
print(' x greater than 4 ')

This is an example..yets it gives expected an indented block error

Answer 4

x = int(input('First number'))
if x > 4:
print('c greater than 4')