+ 1
Result 0 in pointer?
Code sample: https://code.sololearn.com/cxbA0y857Ozf Please tell me why its showing up 0 there.
1 Answer
0
Its result is actually undefined behaviour, when it executes
x++;
++x;
the increment actually increment the value of x, which was the address of y. After that, *x is not the value of y anymore, but some undefined value