Is this not how it works?

Question

There's an error in the or part apparently
https://code.sololearn.com/cZN7L76EoEZ9/?ref=app

Answer 1

one thing I saw is that your input for the (strike:operand)—>operator is still a string but you aren’t comparing to strings in your if statements

Answer 2

I'm trying to write a code for a simple calculator... doesnt using float before the input convert it?

Answer 3

are you making a calculator?
furthermore print(xzy) isn’t going to do anything because you have declared an xzy variable

perhaps you meant print(x,z,y)
but this will not calculate anything, it will simply print numbers and an operator

Answer 4

ERROR_404 yes it does that, but not all types are created equal and you can’t use all types the same. if you do
if z == ‘*’ or z == ‘+’ or etc:
then it will work

Answer 5

have you looked at the lesson in the Python course where it talks about making a simple calculator?

Answer 6

Hi.

Additionally to the points mentioned by Brave Tea you should be comparing the entered operation against string values, i.e. z == '+'