Why % used before a= ,b=,c=,. instead of d in second statement

Question

#include<stdio.h>
Int main(void)
{
Int a=4000, b=200, c=15;
Printf ("a=%d\nb=%d\nc=%d\n",a,b,c);
Printf ("%a=4d\n%b=4d\n%c=4d\n",a,b,c);
return 0;
}

Answer 1

After % whichever alphabet comes first, is considered as format specifier and remaining are printed as it is, here "d" is treated as a normal character.

For example :
Printf("%d is a prime number", n) ;
Here "d" comes first after % so it'll be interpreted as format specifier and will be replaced with the value of n, and remaining characters (" is a prime number") will be printed as it is.

Answer 2

https://code.sololearn.com/cZsMjNE0U4bp/?ref=app

Answer 3

Second printf in your code doesn't produce the output given in that print out.

Answer 4

Aman
As it is now, your second call to printf has 2 valid specifiers, the %a and %c, the %b is in doubt.

I believe without a '%' prefix , (just 'd' alone) is not considered a format specifier, %d is indeed a valid specifier I guess.

Answer 5

Aman
Can you confirm where did you find this snippet? I'd like to have a closer look please.

%d is a specifier for int, if that's what you ask for (I'm not sure). You can check the printf reference I linked on my previous response 👍

Answer 6

And I found it on my college book

Answer 7

Aman
I begin to wonder whether the example in the book was unverified, it makes more sense when the '%' is placed by the '4d' really (like '%4d').

I think we don't call a '%' in a format string as modulo, modulo operator (%) is used between operands (integral value), and not in a string. If I understood correctly.

Answer 8

Guys, statement is wrong written by writer,

Now I got it ,
It should be %4d,

Answer 9

Ipang one of my friend said it's wrong statement, 😅 ,

Answer 10

I wanted to tell you that also, but I need to be confirmed first, don't wanna go jumping into conclusion 😁

Answer 11

%a is a format specifier used to display a value (floating point value) in hexadecimal notation.

%c is a format specifier used to display a value (integral value) as character.

Reference:
http://www.cplusplus.com/reference/cstdio/printf/

But I can't recall any use of %b (or whether it exists). I think the %b is causing a problem here, try to remove %b or add another % prefix so it looks like %%b.

At first I thought you possibly mistaken the placement of the %, and the line could've been probably:

printf ("a=%4d\nb=%4d\nc=%4d\n",a,b,c);

Which is a pretty valid format I guess : )

Hth, cmiiw

Answer 12

Ipang I'm confuse why % separated from (%d) specifier. ???? Is it valid , alone (d) specifier...

Answer 13

https://www.sololearn.com/post/142363/?ref=app

Look at here ,

Answer 14

Ipang than why used (d) 🤔,

Answer 15

And what is it, (d)? It's nor variable and not any symbol than what?

Answer 16

Yes %d is a specifier for int, and before today , I never see module spearted from %d specifier but ya I know 4 is a width length but I did not understand why module not written just before of d, because it should be as I know..

Answer 17

So %4d what were I assume to be.

Answer 18

But it's different so now I'm confused

Answer 19

nidhi
https://www.sololearn.com/post/142363/?ref=app

Look at here ,

Answer 20

? Is wrong statement written on book? 🤔 Tell me