Why this is False⁉️🤔

Question

lst = ["a", True]
print("a" in lst in lst)

Answer 1

It seems to work the same as :

print('a' in lst and lst in lst) ⁉️

Answer 2

Janusz Bujak 🇵🇱 this is what youre after

print(("a" in lst)in lst)

“(“a” in lst)” evaluates True FIRST then tests for “True in lst” which returns True.

Answer 3

Use : print("a" in lst)

Answer 4

Not sure if this help to explain but ..
lst = [1, True, 'a']
lst2 = [[1, True, 'a'], [1, 2], [3, 4], [5, 6]]
print('a' in lst in lst2) ### returns True

Answer 5

That's exactly how it works, Janusz Bujak 🇵🇱.

Answer 6

because,you used in print"a" which is an element. But you should use in print(1st,"in 1st in list")