What's the output of this code AND WHY / EXPLAIN

Question

char* p = "hello"
int n =1;
cout << *(p + --n);

Answer 1

I'll try to explain, but if you are new to pointers, it can be difficult to understand.
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p is a pointer that points to the memory address of first element of the character array.

So writing cout << p; would output a memory address. To output the value of that address, use dereference operator *

i.e. cout << *p; will output "h"

when you write *(p+n), you are accessing the nth element's value. In this code *(p+1) would output "e" because it's the next element in the sequence.

In this code, *(p + --n) = *(p + 0) = *p, so it will output h

To learn more about pointers, watch tutorials on youtube or google about them. It can be a hard topic to learn, but when you understand it, it becomes easy :)