What's the output of this code and WHY/ EXPLAIN cout << (((1||0)&&0)||(1||0)) ;

Question

cout << (((1||0)&&0)||(1||0)) ; !?!?!?!?!?!?!?!?!!??!!??!

Answer 1

the explanation given by hasty is correct but if u want the solution in less time then just see the right () and || before it, so ....anything || (1||0) =1

Answer 2

(((1||0)&&0||(1||0))

(1&&0||1)

0||1

1

This isn't even half bad when compared to the latest batch of validity questions rolled out of the oven.

Answer 3

I like this type of questions very much. It fun fun to answer them especially the lengthy one. With many operators. :)