Guessing game

Question

I’m trying to do a guessing game in {c} but can not figure out how to randomly have 3 chests with 3 values of 500,300,0 chips in them. And if chest 1 is opened and has 300 chips in eliminate that chest so there is 2 left with 500 and 0. And if they choose the chest with 0 they lose all their chips and retry. I’m not good with the srand() and rand() and loops can someone help me out with this?

Answer 1

I'll look into it

Answer 2

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Answer 3

I can help you with that guessing game in C. Here’s a simple example to get you started with srand() and rand() to randomize the values in the chests and implement the game logic:

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main() {
// Initialize random seed
srand(time(0));

// Array to store chest values
int chests[3] = {0, 300, 500};

// Shuffle the chest values
for (int i = 0; i < 3; i++) {
int j = rand() % 3;
int temp = chests[i];
chests[i] = chests[j];
chests[j] = temp;
}

int choice;
while (1) {
//Display available chests
printf("Choose a chest (1, 2, 3): ");
scanf("%d", &choice);

if (choice < 1 || choice > 3) {
printf("Invalid choice. Try again.\n");
continue;
}

choice--; //Adjust choice to 0-based index

// Check the chosen chest
if (chests[choice] == 0) {
printf("You opened a chest with 0 chips! You lose all your chips. Try again.\n");
break; //End the game
} else {
printf("You opened a chest with %d chips!\n", chests[choice]);
chests[choice] = -1; // Mark the chest as opened
}

// Check remaining chests
int remainingChests = 0;
for (int i = 0; i < 3; i++) {
if (chests[i] != -1) remainingChests++;
}

if (remainingChests == 0) {
printf("All chests are opened. Game over.\n");
break;
}
}

return 0;
}

This code sets up an array with the chest values and shuffles them randomly. Then it enters a loop to let the user choose a chest. If they open a chest with 0 chips, the game ends.

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Answer 5

Sure! Here’s a simple approach to implement your guessing game in C:

Use rand() with srand() to randomize the distribution of chip values in the chests.
Keep track of opened chests and ensure they cannot be selected again.
Implement the game logic to handle win/lose scenarios and allow retries.
Here's a sample implementation:

c
Копировать код
#include <stdio.h>
#include <stdlib.h>
#include <time.h>

void shuffle(int chests[], int size) {
for (int i = size - 1; i > 0; i--) {
int j = rand() % (i + 1);
int temp = chests[i];
chests[i] = chests[j];
chests[j] = temp;
}
}

int main() {
srand(time(NULL)); // Seed for randomization
int chests[3] = {500, 300, 0}; // The values in the chests
int revealedChests[3] = {0, 0, 0}; // To track which chests have been opened

shuffle(chests, 3);

int choice, retry = 1;
while (retry) {
printf("\nChoose a chest (1, 2, or 3): ");
scanf("%d", &choice);

// Validate input
if (choice < 1 || choice > 3 || revealedChests[choice - 1]) {
printf("Invalid choice. Try again.\n");
continue;
}

// Reveal the chest
int chips = chests[choice - 1];
revealedChests[choice - 1] = 1;

printf("You opened chest %d and found %d chips!\n", choice, chips);
if (chips == 0) {
printf("You lost all your chips! Restarting...\n");
retry = 0; // End the current loop
} else {
printf("Two chests remain. Can you find the one with the highest chips?\n");
printf("Remaining chests: ");
for (int i = 0; i < 3; i++) {
if (!revealedChests[i]) printf("%d ", i + 1);
}
printf("\n");
}
}

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return 0;
}
Explanation:
Shuffling the chests: The shuffle function randomizes the chip values in the chests using Fish

Answer 6

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