- I need help in understanding this concept

Question

- when learning.. I was told that if an 'if' function is negated once it will only print out the previous correct 'if'..... here is an example... I don't know why 'result' is being printed

x = 4
if x != 3:
print("Yes")
if x == 5:
print("No")
if x <= 5:
print("result")

Answer 1

Blessed-sayah Oyilenaan here is an example.
the last "if" is dependent on the previous one. see how they are nested by indentation.
x = 4
if x != 3:
print("Yes")
if x == 5:
print("No")
if x <= 5:
print("result")

Answer 2

those are independent "if" statements.
each one is evaluated separately the true ones will execute.

and since x <= 5
it will also print "result"

Answer 3

yes, in python blocks of code are determined by indentation. in other programming languages they are mostly defined by { }
example:
if (some condition) {
if(some condition) {

}
}

Answer 4

Basically, it's going through all of these if-statements because elif isnt used. This also gives it the oppertunity to trigger more than one

Consider this:

x = 3

if x == 1:
print("not excecuted")
if x == 3:
print("first excecuted")
if x >= 2:
print("also excecuted")

This is because the interpreter evaluates all three statements

Answer 5

- thanks ... can you give me an example of a dependent "if" statement?

Answer 6

- Thanks.. I've gotten it now... indentation determines if a function is dependent or not