how it work return (f(n-1)+f(n-2));

Question

#include<stdio.h>
int f(int n);
int main()
{
int n,i=0,c;
scanf("%d",&n);
printf("fib\n");
for(c=1;c<=n;c++){
printf("%d\n",f(i));
i++;
}
return 0;
}
int f(int n)
{
if(n==0 || n ==1)
return n;
else
return (f(n-1)+f(n-2));
}

Answer 1

Thank you