Make this program if you dare!!!!!

Question

if the input is 5,then output should be
1
2 9
3 8 10
4 7 11 14
5 6 12 13 15

Note:1.Without Array
2.it is just a program of "Flow Of Control"
i.e. it can be made only with
if condition,loop,cout etc.
3.Don't simply do this:
cout<<"1\n";
cout<<"2 9\n";
cout<<"3 8 10\n";
cout<<"4 7 11 14\n";
cout<<"5 6 12 13 15\n";

Answer 1

#AhriBestAnswer #MostBasic

P.S. Sharma edited his original post to disqualify Ahri. I guess if I start using vectors, he'll add it to the first rule :P

Answer 2

print("1")
print("2 9")
print("3 8 10")
print("4 7 11 14")
print("5 6 12 13 15")
#did I win?

Answer 3

C#:
string s = "ABICHJDGKNEFLMO";
int x = 1, y = 0;
for(int i = 0; i < s.Length; i++)
{
Console.Write(Convert.ToInt32(s[i])-64 + " ");
y++;
if(x == y)
{
y = 0;
x++;
Console.WriteLine();
}
}

You can run the code on my profile 👍

Answer 4

@Ishan Dude, you can't keep making up rules...

Answer 5

Don't know if this is the best way to do it, but I got it to work! Anyways, you can go to my profile and run this in code playground. It also works with n-sized triangles :)

#include <iostream>
using namespace std;

int tri_sum(int val) {
int sum = 0;

for (int i = val; i >= 1; i--) {
sum += i;
}

return sum;
}

int main() {
int n;
cin >> n;

for (int i = 1; i <= n; i++) {
for (int j = 1; j <= i; j++) {
if (j % 2 == 0) {
cout << j*n - tri_sum(j-1) - i + j << ' ';
}
else {
cout << j*n - tri_sum(j-1) - n + i << ' ';
}
}
cout << endl;
}
return 0;
}

Answer 6

@Ahri Fox

😂😂😂😂
Awesome

Answer 7

this is the final rules
i am increasing the rules
because i have program based on input

Answer 8

this is to be done with input i.e. if input is 5
then the above one
and if input is 6 then,
1
2 11
3 10 12
4 9 13 18
5 8 14 17 19
6 7 15 16 20 21