+ 6

C++ from number to binary

The last digit of the binary number is always 1, even when it should be 0. How to solve that? https://code.sololearn.com/cGKLtvYrePal/?ref=app

9th Oct 2019, 6:22 AM
🍇 Alex Tușinean 💜
🍇 Alex Tușinean 💜 - avatar
6 Answers
+ 5
I am beginner in c++ and I have no idea how to do that. 😅
9th Oct 2019, 6:39 AM
🍇 Alex Tușinean 💜
🍇 Alex Tușinean 💜 - avatar
+ 4
As mentioned "the algorithm prints the individual binary digits in reverse order", meaning, if the input is 128, then the output is 0000 0001 which is 1 instead of 1000 0000 This problem can be solved in a variety of ways, but it definitely reminds us of the elegant way a stack works. The stack is a sequential "last in first out" (LIFO) data structure in which the last stored (push) element (on top of the stack) is the first one to return (pop). As for number 128, with a slight change in the algorithmÂč, the stack scheme would be like this when the first `while` block is done, | 1 | <- top | 0 | | 0 | | 0 | | 0 | | 0 | | 0 | | 0 | <- bottom Now, it's ready for poping the stored digits one-by-one from the top to the bottom using the second `while` block, while ( !st.empty() ) { // loop when the stack is not empty cout << st.top(); // print the current top st.pop(); // pop the last item and move the top one cell toward bottom } _____ Âč #include <iostream> #include <stack> using namespace std; int main() { int nr; stack<int> st; cin >> nr; while ( nr > 0 ) { if ( nr % 2 == 0 ) { st.push( 0 ); } else { st.push( 1 ); } nr /= 2; } while ( !st.empty() ) { cout << st.top(); st.pop(); } return 0; }
9th Oct 2019, 7:28 AM
Babak
Babak - avatar
+ 1
Its displayed in reverse, concat it to a string and print that string
9th Oct 2019, 6:29 AM
jtrh
jtrh - avatar
+ 1
🍇 Alex Tusinean 💜, have you worked with arrays in JS? It's almost the same, only the names differ. #include <vector> vector<int> v; And then use the method push_back to add values in the end. Finally: cout it backwards with a loop, again virtually the same as in JS. Use the method size() instead of the attribute length to control the loop.
9th Oct 2019, 6:45 AM
HonFu
HonFu - avatar
10th Oct 2019, 10:27 AM
AliZ