Why output 2?

Question

Hi! Why output 2?
console.log(0 || 1&&2 || 3)

Answer 1

&& has higher precedenceorder than ||.

x && y
Actually means:
x if x equals false, else y

Thus 1&&2 evaluates to 2

x || y
Actually means:
x if x equals true, else y

Thus 0 || 2 evaluates to 2,
and 2 || 3 also evaluates to 2.

0 || 1 && 2 || 3
-> 0 || 2 || 3
-> 2 || 3
-> 2

Answer 2

Thank you very much. I understand now.