Waana know how this program execute, full description please.

Question

public class Program {
public static void main(String[] args) {
int [ ] myArr = {6, 42, 3, 7};
int sum=0;
for(int x=0; x<myArr.length; x++) {
sum += myArr[x];
}
System.out.println(sum);
}
}

Answer 1

For loop runs till 0 to myArr.length
So first itration
x = 0; sum = 0;
sum+=myArr[x] is same as (sum+=6) so sum = 6

second itration
x = 1; sum = 6;
sum+=myArr[x] is same as (sum+=42) so sum = 48

third itration
x = 2; sum = 48;
sum+=myArr[x] is same as (sum+=3) so sum = 51

forth itration
x = 3; sum = 51;
sum+=myArr[x] is same as (sum+=7) so sum = 58

Answer 2

A J Fixed it 😁😅

Answer 3

It's very simple as myArr.length = 4 since there are only 4 elements in the array. So x=0 and 0<4 is true and sum+=myArr[x] means sum = sum + myArr[x] but because already sum is 0 we have sum=0+6 since myArr[0] = 6. Similarly the loop iterates and sum value will become 6+42 in the next iteration and so on till it adds all the elements of the array.

Answer 4

If you say in simple the length of myArr is 4 and you are using for loop where you are adding each elements. Though length is 4 so it will add 4 times like this:-

sum = sum + myArr[0]; 0 + 6 = 6
sum = sum + myArr[1]; 6 + 42 = 48
sum = sum + myArr[2]; 48 + 3 = 51
sum = sum + myArr[3]; 51 + 7 = 58

So final answer will be 58

Answer 5

Sumit Programmer😎😎 Answer will be 58😁