Questions about series

Question

I want to have this
987...1
987..2
.
.
.
9
But I don’t know what I have to write
It’s wrong
https://code.sololearn.com/c6KeOr2wvQ64/?ref=app

Answer 1

Try this
#include <stdio.h>

int main() {
int i,n,j;
for(i=9;i>=1;i--){
for(j=1;j<=i;j++){
n=10-j;
printf("%d",n);
}
printf("\n");
}
return 0;
}

Answer 2

The two codes are exactly the same only

Answer 3

Just with different syntaxLaya Mousavi

Answer 4

Try this
#include <stdio.h>

int main() {
int i,n,j;
for(i=9;i>=1;i--){
for(j=1;j<=i;j++){
n=10-j;
printf("%d",n);
}
printf("\n");
}
return 0;
}

Answer 5

So i did the same patter

Answer 6

I have messaged you in your inbox

Answer 7

https://code.sololearn.com/cuwVQcUP73yc/?ref=app

Answer 8

987654321
987654322
...
...
987654329

Is this what you mean?

Answer 9

Your series(pattern) is not clear to me. Can elaborate please?(give first 5 numbers in the series)

Also there's a bug in your first for loop. You have written

for(i=1;i<=9;i--)
In this case i is 1 when the program starts and it will decrease the i while it's less than or equal to 9.
Well i is always less than 9 in this case so program will run infinitely.

Try this

for(i=9;i>1;i--)

Answer 10

Laya Mousavi
__IAS__ had told you the problem with your loop, please read his review.

This is how I would do it BTW, you might want to cross check what I had changed from your original code : )

int main()
{
int i, n = 9, j;
for (i = n; i; i--)
{
for (j = 0; j < i; j++)
{
printf("%d", n - j);
}
printf("\n");
}
return 0;
}

Answer 11

Trying... __IAS__ Ipang
the pattern is this
987654321
98765432
9876543
987654
98765
9876
987
98
9

Answer 12

would u pls say what is my pattern problem?!(the code that i wrote)