Array question

Question

what is the output of this code?

int nums[] = {1, 3, 2, 4, 6};
if (nums [2] > nums [0])
nums [0] = nums [2];
else
nums [0] = nums [4];
cout << (nums [0] + nums [2] + nums [3])

guys can someone please explain to me how the h*ll can output be 8?..
if nums [0] = num [4] = 6
nums [2] = 2 and nums [3] = 6, the output I get is 14!?
cheers!

Answer 1

nums[2] is 2
nums[0] is 1

if(2 > 1) returns true -> num[0] = nums[2] = 2

Your array looks now: 2, 3, 2, 4, 6
nums[0] + nums[2] + nums[3] = 2 + 2 + 4 = 8

output: 8

Answer 2

thanx a bunch Denise...I thought that else statement was false so I calculated if statement!
SoloLearn Q&A is faster then my IDE ;)