How to compare all the elements of a list with each other?

Question

For example.
I have list
List = [1,5,7,87,9,0]
And I should compare all the elements and find out how many similar items are there

Answer 1

Very good one, Asman-H, but error in line 3 of the code due to the typo "duples" instead of "dupls"

Answer 2

https://code.sololearn.com/ciRHqo7b4FJz/?ref=app

Answer 3

If you want just find out, does the list have duplicate items, use set:

List = [1, 5, 7, 87, 9, 0]
List_without_dupls = set(List)
if len(List) == len(List_without_duples):
print('No duplicates!')
else:
print('There are duplicates!')

How many:

my_list = [1, 2, 3, 4, 1, 1, 2, 2]
my_list_set = set(my_list)
dupls_count = len(my_list) - len(my_list_set)
print('List has', dupls_count, 'duplicates!')

Answer 4

You can also use the count method.

I like this pattern:

for item in sorted(set(that_list)):
print(f'{item}: {that_list.count(item)}')

Answer 5

https://code.sololearn.com/cpfx6TrL5ihp/?ref=app

Answer 6

Title of the code says it all...

https://code.sololearn.com/czQkcFdB8g0D/?ref=app

Answer 7

I must know which elements are equal, (particularly)

Answer 8

https://code.sololearn.com/cP8THc1hqgSt/?ref=app