Why does it return 0 when a[-1]?

Question

int main() {
int a[0];

cout<<a[-1];

return 0;
}

I was asked this question in the C++ challenge. Can someone please explain why? Thankss

Answer 1

If you think that the "return value" is what the cout statement is printing , you are wrong , the code will "print" grabage value each time,
It does return 0 to the process and it does because the last line is "return 0;"

Answer 2

Joey Lim I think here we just declared the array but didn't assign any value and accessing the last element of array which is not present that's why it's giving 0 value.

Answer 3

FlamingArrow yeah, i know the output is 0,not because of the "return 0"

Answer 4

Thanks ppl! now i understand!