Plz can someone help me ??

Question

Write a program in python and an algorithm with algobox named SOM_CHIFFRES, which allows to determine the sum of the digits of a given integer X.
Example: for N = 26418, we will have 2 + 6 + 4 + 1 + 8 = 21)
Change the program to test if x divisible by 3 (algo and pg) in the same folder.
Rq: a number is divisible by 3 if the sum of these digits and divisible by 3

Answer 1

If you break it down, this task is actually quite simple. You try to write this program. If something isn’t working, ask for help. We won’t do your work for you, only point you in the right direction

Answer 2

You don’t need to be smart in mathematics. If you’re struggling with this, you really need to pay attention in class and make sure you understand what your professor is saying. Ask questions if you need to, just be sure to understand

Answer 3

oussama
Looks like you don't have much idea about basic syntax in python, I would suggest to see some 1hr python video on youtube before exam.

Here is the modified code:
a=int(input("donner votre:"))
S=0
while(a!=0):
S=S+(a%10)
a=a//10
print(S)

Answer 4

Well I'll give you what I reached and can you plz fix it for me

Answer 5

Absolutely. As long as you attempt and give it your all, I have no problem helping you

Answer 6

-use // operator to do integer division by 10, to remove last digit of a number
-use n%10 to take last out last digit on integer n.
-make a loop while n is not equal to 0, in each iteration take out last digit of n and add it to some variable sum, and remove last digit from n(modify value of n).

-after loop, check value of sum%3==0.

Answer 7

It's just 4 lines

Answer 8

I have an exam tomorrow and I haven't found a solution for this

Answer 9

Thx

Answer 10

Try this
https://code.sololearn.com/cs6U79NE25sZ/?ref=app
https://code.sololearn.com/c372hPcim4TH/?ref=app

Answer 11

I know but I'm not smart in mathematics

Answer 12

a=int(input(donner votre:))
S=0
b=0
While
b=a%10//10
Print(b)

Answer 13

I mean
a=int(input(donner votre:))
S=0
While
S=a%10//10
Print(b)

Answer 14

def divi3(x):
a=0
for i in str(x):
a=a+int(i)
if not a % 3:
return 1
else:
return 0

divi3(4536)