cin.getline ()

Question

This is the first part of my code
#include <iostream>
using namespace std;
int main() {
int n;
cin >> n;
cin.ignore (n);
char asli [100];
cin.getline (asli,100);
cout << asli;
Its supposed to get a number n which Im gonna need later and then get a string the reason I used cstyle string is because I want to use cin.getline()، but when I input "zohal" its output is "al" instead of zohal
I used different example it never gets the first three characters, why?!

Answer 1

Reason:
This👉cin.ignore(n);
Assume, input as: 4 zohal

Firstly, the computer will assign value 4 to n. As you specified n number of characters to be ignored through cin.ignore(n) predefined function, first 4 characters will be ignored (including spaces/line)

So that, _(1 space)zoh(3 characters) will be ignored.
Hence, Output will be: al

Solution:
just replace cin.ignore(n); with any of the following lines below.
• cin.ignore();
• cin.ignore(1, '\n');
• cin.ignore(1);

Hope this helps. :)

Answer 2

Nobody knows tge reason??