Compile ignore input from user when add new data ...How it solve

Question

#include<iostream>
#include<fstream>

using namespace std;
struct variable
{
char name,sex[5], blood_grp, address, choice;
int donor_no, age;
};
void add_new_data()
{
variable v;
char a;

re_data_enter:
cout << " ===========================================" << endl;
cout << " | BLOOD BANK SYSTEM |" << endl;
cout << " ===========================================" << endl;
cout << endl;
cout << "Enter the Donor no. : ";
cin >> v.donor_no;
cin.ignore();
cout << "Enter the Donor name : " << endl;
cin.get(v.name);
cin.ignore();
cout << "Enter the Donor age : " << endl;
cin>>v.age;
cin.ignore();
cout << "Enter the Donor Sex : " << endl;
cin.get(v.sex,5);
cin.ignore();
cout << "Enter the Donor Blood Group : " << endl;
cin.get(v.blood_grp);
cin.ignore();
cout << "Enter the Donor Adress : " << endl;
cin.get(v.address);
cout << endl;
cout << endl;
cin.ignore();
cout << "Should You Add New Donor Data....(Y/N)" << endl;
cin.get(v.choice);

Answer 1

in: struct variable, you have
char name, sex[5],blood_grp, address, choice ;
that means when you want to add new data
your input have to be one character for name and address.
example when you are asked to enter name, you have to enter one character only like (a) or (b) without parentheses.
try running your program but only enter one character in every input.

Answer 2

your program does not have a main() function, if it is supposed to be the whole thing.

Answer 3

could you put the whole code in sololearn playground and put a link to it.

Answer 4

https://code.sololearn.com/cFhC3z4Fx8I9/?ref=app

Answer 5

It have main () but always ignore user input ....these code are half

Answer 6

Ok

Answer 7

sorry I was busy I couldn't answer you sooner.
in the struct you defined many variables as char. and some of them have to store more than one char. like name, address.
if you want it to work you have to enter one char for every variable except sex[].
i.e Enter The Donor name : a
you can not write more than one char. because that's how you defined name.
change those variables to string.

Answer 8

I CAN NOT UNDERSTAND ....PLEASE DEFINED IN WRITING FORM LIKE CODE WHICH I CHANGING IN CODE

Answer 9

Ok

Answer 10

And also tell next step to solve these problem