Basic c++ game HELP pls

Question

Hi community. Im trying to make a basic game. The main idea is "PC" vs "Player" bet game with this structure:

Menu (start game, exit)
game idea--> pc and player got 100 coins each, player make a bet "1-100 coins".
Game end when player or pc got 0 coins.
game system--> we got 3 boxes ( red, orange, green ) and pc ramdom choose 1 box,
if player choose same box then pc = win,, if no =lose.

1. ¿ How make this random choice for pc between 3 boxes ? "pc_choice"

I will put all new doubts in commends and code when finish.

Answer 1

// Geez, I did it again, didn't I?

#include <iostream>
#include <cstdlib>
#include <ctime>
using namespace std;

int main()
{
srand(time(0));

int PC_coin = 100;
int user_coin = 100;
int menu_selection;
int bet_amount;
string box_choice;
string boxes[3] = {"red", "orange", "green"};

cout << "MENU" << endl;
cout << " - Input 1 to start" << endl;
cout << " - Input any other key to quit" << endl << endl;

cin >> menu_selection;
cin.clear(); cin.ignore(512, '\n');

if (menu_selection != 1)
{
return 0;
}

while (PC_coin > 0 && user_coin > 0)
{
cout << "Please input box choice : ";
cin >> box_choice;
cout << "Please input bet amount : ";
cin >> bet_amount;

cin.clear(); cin.ignore(512, '\n');

if (box_choice == boxes[rand()%3])
{
user_coin -= bet_amount;
PC_coin += bet_amount;
cout << "You lost." << endl;
}
else
if (box_choice == boxes[0] || box_choice == boxes[1] || box_choice == boxes[2])
{
user_coin += bet_amount;
PC_coin -= bet_amount;
cout << "You win." << endl;
}
else
{
cout << "Invalid box type." << endl << endl;
}
}

return 0;
}

Answer 2

@Ace

One day people will be doing srand(no_repeat.Ace()) where the seed will be read from a huge library of oscillating random numbers written by you. :P

Answer 3

@Yuriy az

For now just know that srand(time(0)) randomises rand() so that rand() can "truly" output a random number. Or else, rand() is actually predictable after a few runs.

boxes[rand()%3] has possible results for boxes[0], boxes[1] and boxes[2], which corresponds to the three different boxes. The modulus operator "%" is important to control the range of numbers which you get. For this case, the array size is 3 (indexes 0, 1 and 2), hence, by doing rand()%3, possible results are 0, 1 and 2.

Answer 4

@rei what is cin.clear(); cin.ignore(512, '\n'); Since you r using two cin , so you have to put this cin.clear(); cin.ignore(512, '\n'); after the cin definition???

Answer 5

Rei you are a cheater! <3
in your code pc always win player hahahaha
if you want player win

if (box_choice != boxes[rand()%3])

-------------------------------------------------------

Game is here ( https://code.sololearn.com/c7K05irWcVVO/#cpp ) run it in codeblocks or others.

game still got some defects.

Answer 6

Rei why we use time in that code? " srand(time(0)) "
Also i can use [rand()] for anything to make random choice between different options ?

p.d: Big Rei <3

Answer 7

any sugestion whats wrong here ?

!if i bet more then i got first and later more then 300 i dont got the cout " you dont follow my rules! ? "

do
{
if ((betv<300) && (betv>hum_coin)) {{cout<<" YOU FORGET THE RULES?"<<endl; cin>>betv; cin.clear();cin.ignore(512, '\n');}}
else if (betv<=10) cout<<endl<<" !!PUSSY¡¡"<<endl;
else if (betv<=hum_coin) cout<<endl<<" great"<<endl;
else if (betv>=300) cout<<endl<<" YOU DONT FOLLOW MY GAME RULES !!!!? ok, is fine <3"<<endl;

} while((betv<300) && (betv>hum_coin)); // little chaotic code maybe