how to solve Deja Vu in coach problem

Question

m =list(input())

for i in m :
n =((m.count(i))
print(n)
if (n >1):
print("Deja Vu")
else:
print("Unique")

File "source_file.py", line 6
print (n)
^
SyntaxError: invalid syntax

Answer 1

word = str(input())

word1 = set(word)

if len(word) == len(word1):
print("Unique")
else:
print("Deja Vu")

Answer 2

The above code is incorrect because m.count must be input.count and must be >1 not >=2

Answer 3

I converted input string on set to delete duplicates. Then, i compose lenght of string and set.

Answer 4

Here is my solution

str = input("")
s_str =sorted(str)
c=0
for i in range(len(s_str)):
if(s_str[i]==s_str[i-1]):
c+=1
if c>0:
print ("Deja Vu")
else :
print ("Unique")

Answer 5

input = input()
con= False
for l in input :
if m.count(l) >= 2:
con= True

if con:
print("Deja Vu")
else:
print("Unique")

This is my solution.

Answer 6

inp = input()
for i in inp:
if inp.count(i) > 1:
print("Deja Vu")
break
else: print("Unique")

Answer 7

word = str(input())

import collections
co = collections.Counter(word)
sum = (sum(co.values()))

if sum > len(co):
print("Deja Vu")
else:
print ("Unique")

Answer 8

print((lambda i:'Unique' if sorted(i)==sorted(set(i)) else 'Deja Vu')(input()))

Answer 9

x = input()
list = x.split()
var = list[0]
list = ["a","b","d","e","f","m"]
for x in list:
n = 0
k = 0
while n < len(var):
text = var[n]
n += 1
if text == x:
k += 1
if k > 1:
print("Deja Vu")
else:
print("Unique")
Working 100%
not add all alphabet
you can enter all the letters in the list yourself

Answer 10

palabra = input()
L=set(palabra)
dic={}
for letra in L:
dic[letra]=palabra.count(letra)
valores = list(dic.values())
lista=[]
for elem in valores:
if(elem>=2):
lista.append(elem)
if(len(lista)>0):
print("Deja Vu")
else:
print("Unique")

Answer 11

if you looking for another sulotion for learn :

import re
list = set()

x = input()
for i in x:
y = re.findall(i, x).count(i)
list.add(y)

if max(list) > 1:
print("Deja Vu")
else:
print("Unique")

Answer 12

zin = input()
counter=0
for x in zin:
if zin.count(x) > 1:
counter += 1
if counter > 0:
print('Deja Vu')
else:
print('Unique')

Answer 13

If anyone could fix this problem,

randominput = str(input())
letters = 'aaaaaaaghhhhjkll'

if randominput == letters:
print("Deja Vu")
else:
print("Unique")