Please explain the code below

Question

#include <stdio.h>

void say_hello();

int main() {
int i;

for (i = 0; i < 5; i++) {
say_hello();
}

return 0;
}

void say_hello() {
static int num_calls = 1;

printf("Hello number %d\n", num_calls);
num_calls++;

}

Answer 1

Notice that the say_hello() function defines num_calls as static. That means num_calls will continue to exist after the function exits. So num_calls will keep its value for the next time when the function gets called, and it keeps incrementing after its one-time initialialization to 1.

Answer 2

SpîrîT that is correct, say_hello() is called 5 times from the for() loop, as i counts up from 0 to 4. When i becomes 5 the loop exits without calling say_hello() again.

Answer 3

blackwinter and Brian thank you very much to both.

Answer 4

blackwinter would you explain me about static further more...

Answer 5

blackwinter but the variable is static then how it can change every time?

Answer 6

Brian does it mean the for loop is running the say_hello function to print hello number?