+ 3

Tried solving a code coach problem No numerals but failed one of the test case

https://www.sololearn.com/coach/64?ref=app Here is the code word = input() dic = {0:"zero", 1:"one", 2:"two", 3:"three", 4:"four", 5:"five", 6:"six", 7:"seven", 8:"eight", 9:"nine"} str = "" for i in range(len(word) - 1): if word[i].isdigit() and word[i+1].isdigit(): if word[i + 1] == 0 and word[i] == 1: str +="ten" # continue i += 1 else: str += str(word[i]) + str(word[i + 1]) #print (word[i]+word[i + 1] i += 1 elif word[i].isdigit(): str += dic[int(word[i])] else: str += word[i] if word[-1].isdigit(): str += dic[int(word[-1])] else: str += word[-1] print(str)

7th Feb 2020, 8:05 AM
Joshua Evuetapha
Joshua Evuetapha - avatar
7 Answers
+ 3
The problem is that you code is not converting "10" to "ten" In the *if* statement, you are evaluating string with integers.
7th Feb 2020, 9:03 AM
Arsenic
Arsenic - avatar
+ 2
Thank you, Joshua !! Your code made me laugh at what I did wrong. I had trouble with one of the test cases, too, because ten :) numlist = ["0", "1", "2", "3", "4", "5", "6", "7", "8", "9", "10"] words = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten"] text = str(input()) for i in range(len(numlist)): for char in text: if char == numlist[i]: text = text.replace(numlist[i], words[i]) print(text)
7th Feb 2020, 4:14 PM
Isabel
Isabel - avatar
+ 2
Joshua I copied what you have above into code playground and it gave a type error. As Arsenic mentioned above, word[i] and [i+1] are strings, so Python cannot evaluate them with == 0 or 1 because those are integers. After I put quotation marks around the number (‘0’), the error went away. I used “the zoo has 10 zebras” as a test and your code returned “the zoo has tenzero zebras”. This is because after the initial “if” for 10, your code continued ro search for 0s without regard to whether there is 1 in front. FWIW, I revised my code based on what I learned from you and now it converts both single digits and 10: if "10" in text: text = text.replace("10", "ten") for i in range(len(numlist)): for char in text: if char == numlist[i]: text = text.replace(numlist[i], words[i])
7th Feb 2020, 9:09 PM
Isabel
Isabel - avatar
+ 2
Yes! After adding the if “10” in text, it works with all of Sololearn’s test cases.
8th Feb 2020, 4:29 AM
Isabel
Isabel - avatar
+ 1
Isabel i have a solution to this problem in c++ but similar algorithm doesn't work in python
7th Feb 2020, 8:36 PM
Joshua Evuetapha
Joshua Evuetapha - avatar
+ 1
Did it fix your code Isabel
8th Feb 2020, 4:10 AM
Joshua Evuetapha
Joshua Evuetapha - avatar
0
#try this code line=(input()) dict1={ "0":"zero", "1":"one", "2":"two", "3":"three", "4":"four", "5":"five", "6":"six", "7":"seven", "8":"eight", "9":"nine" } for i in line: if "10" in line: line=line.replace("10","ten") elif i in dict1: line = line.replace(i,dict1[i]) print(line)
20th Jul 2021, 3:17 AM
Sandeep Kumar
Sandeep Kumar - avatar