answer is 3 but can someone please explain how and why :

Question

let a,b,c;
a=1;
b=5;
c=7;

if(++b+a > b++){
console.log(b-4)
}

Answer 1

in the condition, there are left hand side and right hand

left hand side: ++b+a
right hand side: b++

left hand side is evaluated first

++b+a is (++b) + a
a is 1
b is 5
++b is 6,
so (6) + 1
so left hand side is 7

right hand side is b++
b is 6, so right hand side is 6.
then, b++ so b becomes 6 + 1 becomes 7.

Answer 2

in the condition, there is ++b and b++

https://www.sololearn.com/learn/JavaScript/1130/

They both increases b by 1

Answer 3

++b is pre-increment, b becomes 6, and left hand side is 6+1=7

b++ is post-increment, right hand side is 6, and then b becomes 7.

Because 7 > 6 is true,

log 7 - 4 which is 3

p. s. this is bad practice. only good for brain teaser. don't write in this way in real projects.

Answer 4

But the value of b is 5 ,
How come log 7-4 But not 5-4???

Answer 5

So value of b becomes 7..
Thank you 🙏

Answer 6

You need to also know why it is comparing 7 > 6

Answer 7

I got that but couldn't understand how b value became 7