why is the output of this code is 1.0 ,whereas i'm getting an answer of 9?

Question

a = 6
b = 3
a /= 2 * b
print(a)

correct ans: 1.0
My ans : 9

Answer 1

sai a /= 2 * b is the same as:
a = a / (2 * b)

Answer 2

How did you get 9?

Answer 3

Oma Falk answer is 1 and only 1.
a/=2*b implies 2*b calculated at first and then we perform division.
a/=2*b
=> a=a/(2*b) and no other stuff is legal/valid

Answer 4

sai according to your code this will be the only correct answer
The correct answer is 1 as a/= 2*b is same as a/(2*b) = 6/(2*3) = 6/(6) = 1
Hence Proved
Use bodmas to calculate this.
Always use brackets and correct syntax to code.
Hope you had understood

Answer 5

Code to get 9
//write the code
a+= b
//print a with the new value
print(a)

Answer 6

a/=2*b is equivalent to a=a/(2*b)
Therefore,
a=6/(2*3)
=6/6
=1.0

Answer 7

Jishnu Mukherjee that are true words.
.. well 1.0...
I simply debugged the thoughts of sai to understand what made him think it was 9.

Answer 8

2*b must be in ()

Answer 9

it is the priority of operator.
* is higher than /=
and therefore ti. e performed first.

Answer 10

@oma faik but what about associativity as both the * and / have same precedence LTR associativity is used,that is what confusing me

Answer 11

Jishnu Mukherjee
😱😱😱😱😉😉
ups
thanks for debugging

Answer 12

Oma Falk I did jackshit.
first we compute 2*b which is 6 and then divide by a whose value is 6.
so 6/6=1

Answer 13

sai right
but our operators are
/=
and
*

and now it is clear for me why you asked.
you saw
/
and
*

and... Jishnu Mukherjee
a/2 =3
3*3 = 9

lets write it different
a= a /(2*b)