If we do as below ,will value of t calculated in function goes to address of t?

Question

function definition:
int func(int X,int y,int z,int &t)
{t=(X+y+z)/2;}

Answer 1

Actual argument corresponding to t is gets changed as t value, in c++.
Pls Tag language also
In c, you need to use pointer instead of variable to store address. [&t => *t]

Answer 2

You dod not specify a relevant language in thread tags, so

In C you would probably use pointer to pass address of variable <t>.

int func(int X, int y, int z, int* t)
{
*t = (X + y + z) / 2;
// no return value ???
}

In C++ you have the option to use reference.

int func(int X, int y, int z, int& t)
{
t = (X + y + z) / 2;
// no return value ???
}

I think the way <t> is defined in your example isn't quite right if you meant C language, it is fine in C++. And since the function doesn't return anything, you might want to change its return type to `void`. You are returning the result out through the <t> parameter after all.