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Binary gap
Given a positive integer, calculate the maximum distance between 1 in binary representation. For example number 9 has a gap of 2 because its binary representation is 1001. This is my proposed algorithm: Any suggestions to improve it? https://code.sololearn.com/ckupsnCs632F/?ref=app
5 Answers
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Here are my attempts
https://code.sololearn.com/cD67fhI3wbl8/?ref=app
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import re
# version 1. using a function
def max_distance(s):
return max([len(x) for x in re.findall(r"0+", bin(s)[2:])])
print(max_distance(int(input("input a number:- "))))
# version 2 , as a one liner
print(max([len(x) for x in re.findall(r"0+", bin(int(input("input a number:- ")))[2:])]))
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use re.findall to pull all the '0' as a list.
use list comprehension and len function on each item the findall returns to fill that list...
use the max function on that list.
4 lines of code (if you include the import and def a function)
Can also be done as a one liner (2 lines if you include the import statement.
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I like your solution rodwynnejones I did not think of that option. Quick solution and with good performance.