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How is the output 5
public class Program { public static void main(String[] args) { int x=1,y=1,z=0; do{ z=x+y; }while(++x<=1&&y++>=1); z=x+y+z; System.out.print(z); } }
1 Answer
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Initially :
x=1 , y =1 and z=0
During first iterations of loop :
z = x + y = 2;
after execution loop body , condition is checked.
++x <= 1 && y++>=1
This condition fails because first operand (++x<=1) of && evaluates to false. ++x is same as x = x +1;
x is incremented to 2 (2<=1 is false)
As the first operand of && is false it doesn't check for second operand due to short circuit evaluation.
Now outside of loop :
x = 2 ,y=1,z =2
z is assigned result of expression x+y+z that is 2+1+2
Hence the result 5.
edit:
This will help to understand short circuit evaluation :https://code.sololearn.com/cAKZM7vS0yYb/?ref=app