why when i test this the result is 1 when i wrote 1

Question

#include <iostream>
using namespace std;
class elevator
{
private:
int elevator_loc;
public:
void initdata()
{
cout << "\n Enter the floor you on it: ";
cin >> elevator_loc;
cout << "Elevator is now on floor " << elevator_loc;
}
void move_up()
{

elevator_loc = elevator_loc + 3;

}
void move_down()
{

--elevator_loc;

}
void displaydata()
{
cout << "\nYou are now on floor:" << elevator_loc;

}
};

void main()
{
char choice = 'q';
elevator elev1;
elev1.initdata();
while (choice != 'q')
{
cout << "\n Enter + to go up, Enter - to go down, q to quit";
cin >> choice;
if (choice == '+')
{
cout << "You will move up";
elev1.move_up();

}
if (choice == '-')
{
cout << "You will move down";
elev1.move_down();

}
}

elev1.displaydata();

}

Answer 1

Maher Talip ,
I can think of 2 approaches.
1st will be to initialize choice variable to something other than 'q'

char choice ='\0';

2nd approach will be to replace while loop by a do while loop. So that it executes at least once.

do{
//loop body
}while(choice!='q');

Answer 2

That's how you have designed it to work. It shows what you give as input.

`choice` is initialzed to 'q' so while loop is never executed.

Answer 3

thank you bro it's work and i learned something today.thank you again.

Answer 4

i need to use while loop how i can?