Why i cannot write this see the commented below in the following program?

Question

#include <stdio.h>
int pass(int*);
int print(int*);
int main()
{
int a[5];
pass(a);
print(a);
return 0;
}
int pass(int *p)
{
int i;
for (i=0;i<5;i++)
scanf("%d",&a[i]); // instead of scanf("%d",p+i);
}
int print(int *p)
{
int i;
for (i=0;i<5;i++)
printf ("%d",a[i]); // instead of printf("%d",*(p+i));
}

Answer 1

'a' has a scope limited to main function. It cannot be accessed inside the pass or print method.

Answer 2

Since you have passed the pointer(p) and not a, the function doesn't recognize what is 'a' , if you want to use 'a' , make the array public instead of declaring in the main() function.

Answer 3

Also, pass() and print() functions doesn't return any value , so change it to

void pass(int *);
void print (int *);

Similarly change in the definition also.