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Are the location of arguments different?

It the example we have: squares [3]= 9 Then in the result, we have: {1:1, 2:4, 3:9,...} Does this mean that when dealing with dictionaries, bytes start counting from 1 and not 0? In other words, for a list: [ "a", "b", "c", "d"] location of a is 0 location of b is 1 and so on...

20th Mar 2020, 4:52 PM
sarah
sarah - avatar
2 Answers
+ 2
Not exactly, in the dictionaries you put the value of the index, it is not an obligation that starts is 1. As for the lists, the index of each element is placed automatically and always indicates from 0
20th Mar 2020, 5:08 PM
Cmurio
Cmurio - avatar
+ 1
In dictionaries, the value is accessed through a key. In your case, in the dictionary 1 is the key for 1 So squares[1] will give 1 2 is the key for 4 So squares[2] will give 4 3 is the key for 9 So squares[3] will give 4 If the dictionary was cubes ={1:1, 2:8, 3:27} So cubes[3] would give 27. Even if the keys were not in order it would be the same cubes = {3:27, 1:1, 2:8} cubes[3] would still give 27
20th Mar 2020, 5:17 PM
XXX
XXX - avatar