#define( macro) order of execution.

Question

Could anyone please explain Me.
How the code below, executes.

Means, what's the order by which each line/statement executes.

I thought the output should be : 11 6 11.
But it's 12 6 11?...
https://code.sololearn.com/cTfE5Mit5Qmk/?ref=app

Answer 1

Macros work differently from functions.
"Macro expansion" is like a dumb copy-paste.

After macro expansion, your line 6 becomes:

k=((i++)>(j++)) ? (i++):(j++);;

Which should explain the strange result. (Also note the extra ";" !)

When using macros you always have to be extra careful.

Answer 2

Thanks Schindlabua...