Compile time error

Question

Find error and decode it
https://code.sololearn.com/cNB0kf6JYuFt/?ref=app

Answer 1

Thanx for clear my doubts Sheetal Malavade 😊

Answer 2

Avinash Giri Sure 👍

Answer 3

Avinash Giri , your variables x and y are not initialized. You can give them a value or use Scanner to ask user to input something.

Answer 4

Avinash Giri , what is the purpose of your code?

Answer 5

Yeah Sheetal Malavade

Answer 6

class name should start with capital letter
and also variable x is undeclared

Answer 7

make the class name as Debugging instead of debugging because java allows class names which start with a capital letter

Answer 8

declare the x value

Answer 9

But condition is not apply if I give x=3 they give me y =3 but don't check if conditionTheWh¡teCat 🇧🇬 Baci

Answer 10

What happens when x= 3 they fulfil the condition. (x>10)TheWh¡teCat 🇧🇬

Answer 11

It's not clear what is the idea of your code, Avinash Giri.

Answer 12

Put the x value in y but use if TheWh¡teCat 🇧🇬 plzz clear my doubt

Answer 13

It's not clear, only you know what do you want to do with your code, but you don't explain it, Avinash Giri.

Answer 14

Plzzz explain it I see this question in my book so I try to solve thisTheWh¡teCat 🇧🇬

Answer 15

import java.util.*;

// Compiler version JDK 11.0.2
import java.util.Scanner;

class debugging
{
public static void main(String args[])
{
Scanner sc=new Scanner(System.in);
int x= sc.nextInt();

int y;
if (x<10)
{
y = x;
}
System.out.println(" Value of Y = "+x);
}
}
Now code is right plzz explain output
TheWh¡teCat 🇧🇬

Answer 16

Avinash Giri
the logic you have written in this program will take input X from user and checks whether it's less than 10 or not..
there is one correction in your last printf statement.. that is if you want y data to be displayed then change your code to
System.out.println("value of Y = " + y ) ..
but you have written X there ..

program will works like this ..

1. if it's less than 10 , then it will enter into if block and assigns X value to y . (y=X)
and prints the same output.
2.if X is greater than 10 suppose X= 15 , then it is false and skips the if block. and program control jumps to print statement..
he there is a small mistake would occur .. when the X value is greater than 10 , it wil never enter the if block and there wont be any value assigned to y.. and program control jumps to print statement.. since you have not initiatialised y variable in the beginning , hence it will throw error .. so 1st assign value to y so that it can print the default y value when X > 10..

Answer 17

Variable x is not declared

Answer 18

Hello Giri
I want you to help me