0
help me solve this
https://www.sololearn.com/coach/77?ref=app text= input() sub_string1= 'T
#x27; sub_string2 = '$T' sub_string3='G$G' list = [] for i in text: if( i != 'x'): list.append(i) text1 = ''.join(map(str,list)) a=(text1 .find (sub_string1 )) b= (text1 .find (sub_string2 )) c=(text1 .find (sub_string3 )) if(a != -1 ): print ("ALARM") elif(b != -1): print ("ALARM") elif(c == -1): print ("ALARM") else: print ("quite") it is satisfying only 3 test cases .I don't what is the mistake rest of cases are hidden,I tried using 'and ' 'or' conditions also but the result is same
3 Answers
+ 2
1- print("quiet") not quite
2- You don't need substring_3 at all. Remove elif(c==-1)
That's it
+ 2
Also you shouldn't use list as a variable name because it's already a built-in of the language.
+ 1
ok tq
Often have questions like this?
Learn more efficiently, for free:
Hot today
Kernel in Jupyter
2 Votes
SQL
2 Votes
JAVA PROGRAMMING
1 Votes
What Does Pseudo Elements Mean.
2 Votes
IMAGE
0 Votes