Data Science - Average of Rows. Has anybody solved this Code Coach Challenge⁉️ - SOLVED

Question

My code doesn't pass the last, #5️⃣ test‼️ Any ideas⁉️🤔

Answer 1

My code:

n, p = [int(x) for x in input().split()]

rm = [] # rowmean
[rm.append(round(sum([float(i) for i in input().split()])/p, 2)) for j in range(n)]

import numpy as np
print(np.array(rm))

Outputs: test case #5️⃣

my: [1.95 2.23 2.67 1.62]
#5️⃣: [1.95 2.22 2.68 1.62]
difference: +0.01 -0.01

Probably the problem is in number rounding ⁉️🤔
my: round(x,2)
other: x.round(2)

Sorry‼️I can't show in public the code which has passed all 5️⃣ tests‼️☹️

Answer 2

I have used np.around and it worked!
https://docs.scipy.org/doc/numpy/reference/generated/numpy.around.html

Answer 3

"For values exactly halfway between rounded decimal values, NumPy rounds to the nearest even value. Thus 1.5 and 2.5 round to 2.0, -0.5 and 0.5 round to 0.0, etc. ... "
Notes from: docs.scipy.org/doc

Answer 4

Interesting 🤔 but in this code coach that's not going to happen because we are rounding to 2 decimal places not to an int value we don't need that method.
Janusz Bujak 🇵🇱
I was on the right track. Problem wasn't the round functionality at all but the way you calculated the mean. Replace your sum()/p logic with nparray.mean() and your code will work even when you used the round(x,2) form.

Answer 5

Janusz Bujak 🇵🇱 You are right. I misunderstood that sorry.

Answer 6

Which challenge you are talking about, guys? Can you send a link?

Answer 7

Kuba Siekierzyński
https://www.sololearn.com/coach/111?ref=app
Data Science - Average of Rows

Answer 8

Dzięki, Janusz Bujak 🇵🇱 , I couldn't find it on the code coach list... 🤔

Answer 9

Kuba Siekierzyński You must advance in your course and the challenge will be available as a DM from SL.

Answer 10

BEN_10🇮🇳
Besides the 72 CCC accessible from the Learn tab, there are 10 more CCC (Python only) related to Data Science and Machine Learning courses which will be available as DM from SL as you advance through the mentioned courses.

Answer 11

Erik Gordon-Quaicoe
Amir Mehrabi Jorshari

import numpy as np
n, p = [int(x) for x in input().split()]
m = []

[m.append([float(i) for i in input().split()]) for j in range(n)]
print(np.mean(np.array(m), axis=1).round(2))

Answer 12

No idea. I already solved it so you can DM me because its Pro.

Answer 13

I don't know. This looks like another rounding issue. I used the numpy array mean and round functions and it works.
Right now I don't know if the problem is rounding or the division operator.

Answer 14

Kevin Star
Sorry but this note applies to all rounding levels:
https://code.sololearn.com/cSmkN8fGY6dG/?ref=app
Thanks for your advice but I've already solved this CCChallenge‼️🙂

Answer 15

can anyone help me with test case #1 at least to get the concept so that i can research the rest on my own. I’m really stuck. please

Answer 16

Erik Gordon-Quaicoe Read the PROBLEM again & all A in this Q&A‼️ Pay close attention to problems with round(), read about numpy mean & show me your code‼️😃

Answer 17

Janusz Bujak 🇵🇱 import numpy as np

ls = []
for i in range (2):
ls.append(input().split())

ls_arr = np.array(ls)
rm = ls_arr.astype(float)
print (np.mean(rm, axis=1))

Answer 18

the Numpy has already a round function.

n, p = [int(x) for x in input().split()]
import numpy as np

ls = []
for i in range (n):
ls.append(input().split())

ls_arr = np.array(ls)
rm = ls_arr.astype(float)
result = np.mean(rm, axis=1).round(2)

Answer 19

Data Science - the perfect solution for average of rows

n, p = [int(x) for x in input().split()]

import numpy as np

rm = []
for i in range(n):
for a in input().split():
rm.append(float(a))
a = np.array(rm).reshape((n,p))
c = np.mean(a,axis=1)
p = np.around(c,2)
print(p)