Sir please tell me how it was functioning.......what way the compiler is understanding..... Plz sir..... Tell me

Question

https://code.sololearn.com/c7ZetlUCLxlT/?ref=app

Answer 1

I think

#define sqr(i) i*i

So for

sqr(3+1)

It is

3 + 1 * 3 + 1

== 3 + 3 + 1

== 7

If you put a bracket as

sqr((3+1))

it will be

(3+1) * (3+1)

== 4 * 4

which is 16

Answer 2

Tq Broo....