What does ++x mean and also what does y-- mean

Question

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Answer 1

Let's take a simple example,

int x = 3;int y = ++x;

In this both var 'x' and var 'y' become 4 as the compiler increases the value immediately.

However, here..

int a = 4;
int b = a--;

var 'a' becomes 3 and 'b' becomes 4 because the compiler first assigns the value of var 'a' to var 'b' and then depreciates the value of var 'a'

Hope this helps :)

Answer 2

"do first what you see first"
int x= 3;
int y = 0;

y = x++
//first you see x so first assign x, then increment x
here y=3 and x=4

but

y = ++x

//first you see ++ so first increment x then assign
here y=4 and x=4

Answer 3

++x means "add 1 to x then evaluate x"
y-- means "evaluate y then subtract 1 from y"

They are similar but different.

For example,

int x = 5;
System.out.println(++x);

prints 6 because println evaluates x AFTER calcurating 5 + 1.

In contrast,

int x = 5;
System.out.println(x++);

prints 5 because println evaluates y BEFORE calculating 5 + 1.