🆘 Maybe it's something wrong with me but I don't understand why in the 🐍 code:

Question

class C: # C(int) --> True
pass
a, b = C(), C()
print(a == b) # False

🅰️ & 🅱️ are different 🤔

Answer 1

Not if you don't implement it. Then you inherit the __eq__ implementation of 'object', and that compares id (so basically like is).

Answer 2

HonFu You are reliable‼️Thx‼️
Tomorrow I'll implement __eq__ 🙂

Answer 3

class C:
pass

a, b = C(), C()
print(a)
print(b)

Output shows two different memory address.

Answer 4

RKK Thx, I know‼️🙂
But "==" checks equality and not identity like "is"‼️🤔

Answer 5

Morning, fresh mind, fresh ideas. Yesterday, after hard day I stucked on a trivial 🐍 problem, solved already‼️
Thx HonFu, RKK, rodwynnejones ‼️🙂
"Don't think that you can think when you can't think - take a rest‼️"

class C: # __eq__ implemented
def __eq__(self, other): # f.ex
return True if type(self) == type(other) else False

a, b = C(), C()
print (a == b) # True
print (a is b) # False

Answer 6

If you haven't implemented == (__eq__) for your type, it returns the memory address of your object.

Since you create two separate objects, the result will be False.

Answer 7

If your trying to check if a and b are instances of the same class then the "type" function:-
class C:
pass

a, b = C(), C()
print(type(a) == type(b)) #< outputs true