Can anyone solve this misunderstanding???

Question

Question :
double a= 0.1;
double b=0.2;
double c=0.3;
If (a+b==c)
Cout<<"yes";
Else
Cout<<"no";
//Why no it's outputed??
//Is it because it's value is same but reference is different like variable a,b and c are different references??

Answer 1

Yes

Answer 2

Yes .. Actually I forgot to do that

Answer 3

Is it reference concept .. If when it is reference and when value??

Answer 4

https://code.sololearn.com/cpcn5vq99O29/?ref=app

https://code.sololearn.com/clm1vHX8oEYf/?ref=app

Just see this I have done these in C and CPP so that u can find the difference. Actually 0.1+0.2 is not equal to 0.3 since it's equal to 0.3000000000004 something.. so just check this one Prathik Shetty

Answer 5

It's only a matter of values, here. The thing is that c is not initialized, that means that it holds some garbage value (or 0, I don't know about the C++ behavior about uninitialized value).

Whatever, a+b is 0.3 and c is unknown (and you will have only a few chances to have c = 0.3) so a+b != c : it outputs "no".

Answer 6

Théophile c is initialized with 0.3?

Answer 7

But wait... You changed your question... When I answered to it, c wasn't initialized to 0.3.