Selecting the right product in python

Question

How to implement a function selection(products, conditions)

Input: phones and conditions
Output: the list of products satisfying all conditions

Examples:
>>> selection(phones, [cheap, large_screen])
[[‘Reno Z’, ‘Oppo’, 6.4, 4035, 397])

>>> selection(phones, [not_apple])
[[‘GalaxyS20’, ‘Samsung’, 6.2, 4000, 1348],[‘Nova 5T’, ‘Huawei’, 6.26, 3750, 497],[‘Reno Z’, ‘Oppo’, 6.4, 4035, 397]]

Answer 1

Try using a Named Tuple.
I think I have an example to post for you to play with.
Let me look

Answer 2

Ok - Named Tuple attached.
Input 01 or 02 or 03 to get a result.
Then you can see how the code works

https://code.sololearn.com/cYtN0UazY6Qr/?ref=app

Answer 3

Or you could use OOP

https://code.sololearn.com/cgwfEkS3aB1S/?ref=app

Answer 4

this is my attempt:

Cheap = (4, ‘<=‘, 400)
Large_screen = (2, ‘>=‘, 6.3)
not_apple = (1, ‘!=‘, ‘Apple’)

def selection(products, conditions):
for i in range(len(conditions)-1):
if conditions[i] == cheap:
index = cheap[0]
value = cheap[2]
if conditions[i+1] == large_screen:
index1 = large_screen[0]
value1 = large_screen[2]
for j in products:
if products[j][index] <= value and products[j][index1] >= value1:
return products[j]

Answer 5

But it seems to be not working. If anyone could help, please correct me whereever i went wrong in my code.

Answer 6

yes... please send it through. Thank you Rik Wittkopp

Answer 7

Phones = [[‘Iphone11’, ‘Apple’, 6.1, 3110, 1280],
[‘GalaxyS20’, ‘Samsung’, 6.2, 4000, 1348],
[‘Nova 5T’, ‘Huawei’, 6.26, 3750, 497],
[‘Reno Z’, ‘Oppo’, 6.4, 4035, 397]]
Conditions:
Representing the conditions as triples (i, c, v) where i is and integer feature index, c is a relation symbol and v is some feature value.
Cheap = (4, ‘<=‘, 400)
Large_screen = (2, ‘>=‘, 6.3)
not_apple = (1, ‘!=‘, ‘Apple’)