Find the minimum (python)

Question

Implement a function find min(lst, index) that takes a list of orderable items and an index as input. The function returns the index of the smallest item in lst[index:]. If there are duplicate values, then the function returns the smaller index.

# Example :
>>> find_min ([ ' candlestick ', 'pipe ', 'rope ', 'knife ', 'wrench '] , 2)
3
>>> find_min ([1 , 3 , 5 , 11 , 7 , 3 , 2 , 6 , 2] , 3)
6

My attempt is in the comment
https://code.sololearn.com/c369wAQs9rIp/?ref=app

Answer 1

𝐊𝐢𝐢𝐛𝐨 𝐆𝐡𝐚𝐲𝐚𝐥 sorry that was a typo.. but i still get 0 for the output

Answer 2

𝐊𝐢𝐢𝐛𝐨 𝐆𝐡𝐚𝐲𝐚𝐥 yeah it works, thank you.
Can you please explain why did you ‘+ index’ in the return ???

Answer 3

𝐊𝐢𝐢𝐛𝐨 𝐆𝐡𝐚𝐲𝐚𝐥 right, that makes sense. thank you :))

Answer 4

my attempt:

def find_min(lst, index):
lst1 = lst[index:]
min_lst1 = min(lst1)
lst2 = lst.index(min_lst1)
return lst2

>>>lst = [5,2,3,10,1,10,5,6,5,8,10]
>>> find_min(lst, 8)
0

instead of 0, how can i get 8? for the index num 5

Answer 5

Jay Matthews 𝐊𝐢𝐢𝐛𝐨 𝐆𝐡𝐚𝐲𝐚𝐥 i posted my attempt in the comment above

Answer 6

𝐊𝐢𝐢𝐛𝐨 𝐆𝐡𝐚𝐲𝐚𝐥 8