Different output , why?

Question

var m = parseInt("0*10");
var k = parseInt("0x10");
console.log(m);
console.log(k);

Answer 1

Md. Iftakher Hossain Hello there :))

0x is base 16 that is, anything after it will be considered as a hexadecimal value. To check :

console.log(0x1) // 1
console.log(0x9) // 9
console.log(0x10) // 16

Because 10 in hexadecimal means 16 in decimal.

Proof :

console.log(0x10 == 16) // true

So parsing it as a int will result in 16.

And 0*10 = 0, so parsing it as a int will result in 0!

Answer 2

Md. Iftakher Hossain
0x means the number is hex, or base 16.

0x10 is 16

Answer 3

Arb Rahim Badsa

Slight correction:

parseInt("0*10") // output is 0, extracting the characters from the beginning of the string if it is a number character. And convert it into number.
It's not an evaluation like eval() method.
you already know😉

Eg:

parseInt("3*5") //output : 3

Answer 4

Thanks for the correction bro :)) Kelvin Paul

Answer 5

Arb Rahim Badsa
You are welcome 😌😉

Answer 6

Md. Iftakher Hossain

parseInt ("10",8) // returns 8

It converts base8 number 10
into base10:
Octal 10 is equal to Decimal 8

You can use parseInt method to convert any base to decimal value.
(From base2 to base32)

toString() is much similar to parseInt.

0x45.toString(8) // returns 105

Converting hex to octal

I mean

var x = 0x45 // hex number
console.log(x.toString(8)) // Output:105

Answer 7

Thanks all.

Answer 8

Kelvin Paul Thanks.

Answer 9

("0*10") and ("0x19")
you are trying to parse it to Integer.

Answer 10

Arb Rahim Badsa Thanks.

Answer 11

Md. Iftakher Hossain you are welcome ☺