When we use operation 15/2 ,how can we get output as 7.5

Question

Please

Answer 1

I assume you are talking about C++, which you have started, or a comparable language.

If you write 15/2 in your code, both these numbers are ints. That means they have no decimals.

So 7.5 becomes just 7.

Even if you write...

double d = 15/2;

... this doesn't help, because the result of two ints is first calculated, then converted to double. Result: 7.0.

The trick is to make one of the operands a double literal.

So write either 15/2.0 or 15.0/2.

Answer 2

HonFu We can just do typecast like this

int a = 15;
int b = 2;

cout << (double) a/b;

Answer 3

Somendra mention the language please.

in Java we can do like this

int a = 15;
int b = 2;

double d = 0.0;

d = (double) a / b;

System.out.println(d);

In C++
-----------

int a = 15;
int b = 2;

cout << (double) a/b;

Answer 4

Yeah, AJ, and that.