I want to print something if(txt1="abc") textview value will be same as i given in string. But i always getting error.

Question

Android Studio: (Java) Code are here....

m1.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
txt1.setText(txt1.getText().toString()+"a");
m1.setEnabled(false);
}
});

m2.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
txt1.setText(txt1.getText().toString()+"b");
m2.setEnabled(false);
}
});

m3.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
txt1.setText(txt1.getText().toString()+"c");
m3.setEnabled(false);
}
});

m4.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
txt1.setText(txt1.getText().toString()+"d");
m4.setEnabled(false);
}

Answer 1

I think txt1 is text component then may be

if(txt1.getText().equals("abc")) is you need.

Answer 2

You have to use double equality
==

Answer 3

Thanks Jayakrishna🇮🇳 It's Worked. I stuck in same from last 2 days.

Answer 4

I'm glad that helped you..
Gorishankar You're welcome..