Can someone help me out with type conversion please

Answer 1

Thank youuu

Answer 2

Käī Just write it like so :

num1 = int(input('Enter a number'))
num2 = int(input('Enter another number'))

print(float(num1*12) + float(num2*6))

Answer 3

In which language?

Answer 4

Python

Answer 5

To make integer to string :

str(10) # '10'

To make string to integer :

int('10') # 10

To make int to float

float(10) # 10.0

Answer 6

Hey I have another question
How do I do
Print(float(input("enter a number: "))) +
Float(input("enter another number:"))

Answer 7

Thanks :))

Answer 8

Srry to bother you again but I got a error
When I did this:
print(float(12*int("Enter a number: ")) + float(6*int("Enter another number: ")))

num1 = float(12*int('Enter a number:'))
num2 = float(6*int('Enter another number'))

print(num1 + num2)

Answer 9

Did I do something wrong

Answer 10

You could also do something like:
print(float(input('Enter a number:')) + float(input('Enter another number:')))
You just had to move ')' to the end.

Answer 11

Hey it's me again I did it but I still got a error:
num1 = int(12('Enter a number:'))
num2 = int(6('Enter another number'))
str(12) # 12.0
str(6) # 6.0

print(float(num1*12) + float(num2*6))

Print(float(input("Enter a number: ")) +
float(float(input("Enter another number: ")))

Answer 12

Here you go :))

num1 = float(input('Enter a number'))
num2 = float(input('Enter another number'))

print(num1 + num2)

Answer 13

Hey I tried ur way but am still getting error

Answer 14

I tried this

num1 = float(int * 12('Enter a number:'))
num2 = float(int * 6('Enter another number'))
print((num1 * 12) + (num2 * 6))

Answer 15

this app is so helpful ! XD

Answer 16

You can do this:
integer = int(input())
integer2 = int(input())
print(integer * integer2)