Why is the output of this code: None 2

Question

https://code.sololearn.com/cfF3QVGCOwxE/?ref=app

Answer 1

It will always return 1 in each condition. Here your fornication is acting just like a loop infact it is not a loop. by the way here result is 1 2

Answer 2

The correct format should be like this:

def function(x):
if x == 1:
return x
else:
x -= 1
return x

function(x)
x = 2
print(function(x),x)

Kindly upvote if it works for you.
Thanks 😊

Answer 3

Try running the code you get output as :
None 2

Answer 4

But when you run the code we get output as:
None 2

Answer 5

Thanks ,I understood
Can you upvote my question 😀

Answer 6

https://code.sololearn.com/cVWBwfU6L390/?ref=app

Answer 7

Second last line of your code has intendation, thus it is not a part of your function.
As a result of which value of x is 2. And when yoy call a function outside of its defination it returns none.