How can I found the element's index in the string

Question

For example:

a = "XKLMN"

for i in a:
if (i == "M"):
print(" index of 'M' is : ")

Answer 1

a = "XKLMN"
print(a.find('M')) # returns -1 if the value is not found.
print(a.index('M')) # raises an exception if value not found.

Answer 2

a = "MXKLMN"
x = 'M'

You can use index(), but if the desired character can not be found, a ValueError will be raised, and the program will be terminated. you could avoid this with a try... except block:

print(a.index(x))

Or you use find(), that also gives an index back, but does not cause an error if the desired character cannot be found. In this case it returns -1:

print(a.find(x))

Or let's assume we have a string, that may contain more than one of the desired character. So var "a" contains 2 x "M":

print(*[i for i, e in enumerate(a) if e == x])

In this last example you will get all index positions of the desired character back

Answer 3

Create a counter variable assigned to zero and increase it by one each iteration.

edit:
or
print (a.index ('M'))