Can anyone explain why it's printing "panni" instead of "-23 23"

Question

int main() {
unsigned int i = 23;
signed char a = -23;

if(i>a)
printf("%d %d",a,i);
else if(i<a)
printf("panni");

return 0;
}

Answer 1

You are actually comparing signed and unsigned values. Because 'i' is at first place, C convert 'a' to an unsigned value...

As you know, -23 > 23 (if you don't understand why, search for the binary representation of a negative value), so it is false.

If you're working in C, try to cast 'i' to a signed value.

Answer 2

I don't know if that's the issue but I'd use if / else instead of if / else if

Maybe you're missing an else statement?

Then again I'm not familiar with signed / unsigned comparison

Answer 3

Théophile can you elaborate what value it (a) will be converted ?? And how the conversion happens?

If there any study link please share. It'll be more helpful